A photograph

A photograph will stick to a white square letter with a x cm length. The photo is 3/4 x cm long and 20 cm wide than the width of the paper. The surface of the remaining paper surrounding the photograph is 990 cm2. Find the size of paper and photo.

Correct result:

a =  39.846 cm
b =  29.885 cm
c =  20 cm

Solution:

S1=a2 b=3/4 a c=20 S2=b c S1S2=990  a23/4a20=990  a23/4 a 20=990 a215a990=0  p=1;q=15;r=990 D=q24pr=15241(990)=4185 D>0  a1,2=q±D2p=15±41852=15±34652 a1,2=7.5±32.3457879793 a1=39.8457879793 a2=24.8457879793   Factored form of the equation:  (a39.8457879793)(a+24.8457879793)=0  a=a1=39.8458=39.846 cmS_{1}=a^2 \ \\ b=3/4 \cdot \ a \ \\ c=20 \ \\ S_{2}=b \cdot \ c \ \\ S_{1}-S_{2}=990 \ \\ \ \\ a^2 - 3/4*a*20=990 \ \\ \ \\ a^2 - 3/4 \cdot \ a \cdot \ 20=990 \ \\ a^2 -15a -990=0 \ \\ \ \\ p=1; q=-15; r=-990 \ \\ D=q^2 - 4pr=15^2 - 4\cdot 1 \cdot (-990)=4185 \ \\ D>0 \ \\ \ \\ a_{1,2}=\dfrac{ -q \pm \sqrt{ D } }{ 2p }=\dfrac{ 15 \pm \sqrt{ 4185 } }{ 2 }=\dfrac{ 15 \pm 3 \sqrt{ 465 } }{ 2 } \ \\ a_{1,2}=7.5 \pm 32.3457879793 \ \\ a_{1}=39.8457879793 \ \\ a_{2}=-24.8457879793 \ \\ \ \\ \text{ Factored form of the equation: } \ \\ (a -39.8457879793) (a +24.8457879793)=0 \ \\ \ \\ a=a_{1}=39.8458=39.846 \ \text{cm}

Checkout calculation with our calculator of quadratic equations.

b=3/4 a=3/4 39.8458=29.885 cmb=3/4 \cdot \ a=3/4 \cdot \ 39.8458=29.885 \ \text{cm}
c=20 cm  S1=a2=39.845821587.7037 cm2 S2=b c=29.8845 20=597710=597.7 cm2c=20 \ \text{cm} \ \\ \ \\ S_{1}=a^2=39.8458^2 \doteq 1587.7037 \ \text{cm}^2 \ \\ S_{2}=b \cdot \ c=29.8845 \cdot \ 20=\dfrac{ 5977 }{ 10 }=597.7 \ \text{cm}^2



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