Car goes from point A to point B at speed 86 km/h and back 53 km/h. If they goes there and back at speed 67 km/h trip would take 10 minutes shorter. What is distance between points A and B?


s =  258.4 km


t1=t2+1060 s86+s53=2s67+1060 s=1060(186+153267) s=258.4  km t_1 = t_2 + \dfrac{ 10 }{60} \ \\ \dfrac{s}{ 86 } + \dfrac{s}{ 53 } = \dfrac{2s}{ 67 } + \dfrac{ 10 }{60} \ \\ s = \dfrac{ 10 }{ 60 ( \dfrac{1}{ 86 } + \dfrac{1}{ 53 } - \dfrac{2}{ 67 } ) } \ \\ s = 258.4 \ \text{ km }

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