Surveyor

Calculate the area of ​​what may vary rectangular, if it focused by surveyor and found the dimensions 10 x 16 m while in each of the four joint points can be position deviation 8 cm?

Correct answer:

Δ =  2.94 m2

Step-by-step explanation:

a=10 m b=16 m o=8 cm m=8:100  m=0.08 m  o2=c2+c2 c=o/2=0.08/20.0566 m  S=a b=10 16=160 m2 S1=(a+c) (b+c)=(10+0.0566) (16+0.0566)161.474 m2 S2=(ac) (bc)=(100.0566) (160.0566)158.5324 m2  Δ=S1S2=161.474158.5324=2.94 m2



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