# Copper sulphate

How much g of water do we have to add to 240 g of an 84% CuSO4 solution to produce a 60% solution? (Express the mass of crystalline CuSO4 in the original solution and in the resulting solution and compare them. )

Result

w =  96 g
m1 =  201.6 g
m2 =  201.6 g

#### Solution:

0.84*240 = 0.60 *(240+w)

0.6w = 57.6

w = 96

Calculated by our simple equation calculator.
$m_{ 1 } = 0.84 \cdot \ 240 = 201.6 = \dfrac{ 1008 }{ 5 } = 201.6 \ \text { g }$
$m_{ 2 } = 0.60 \cdot \ (240+w) = 0.60 \cdot \ (240+96) = \dfrac{ 1008 }{ 5 } = 201.6= \dfrac{ 1008 }{ 5 } = 201.6 \ \text { g } \ \\ \ \\ m_{ 1 } = m_{ 2 }$

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