Lid

What is the weight of concrete cover (lid) to round shape well with a diameter 1.8 m, if the thickness of the cover is 11 cm? 1 m3 of concrete weighs 2190 kg.

Result

m =  613 kg

Solution:

m=ρV=ρπr2h m=π2190(1.8/2)211/100=613  kg m = \rho V = \rho \pi r^2 h \ \\ m = \pi \cdot 2190 \cdot (1.8/2)^2 \cdot 11 / 100 = 613 \ \text { kg }







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