# The hiker

The hiker will travel 40% of the route on the first day 1and/3 of the rest od second day. Last day 30 km. What was the length of the 3-day trip? How many kilometers did he walk each day?

Result

a =  30
b =  15
c =  30
t =  75

#### Solution:

a+b+c=t
a = 40/100t
b = 1/3*(t-a)
c = 30

a+b+c-t = 0
100a-40t = 0
a+3b-t = 0
c = 30

a = 30
b = 15
c = 30
t = 75

Calculated by our linear equations calculator.

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