Cyclists

The cyclist who rides at an average speed 16 km/h travels a trip distance 10 min before the cyclist who rides at an average speed 11 km/h.

What is the length of this cyclist trip(distance in km)?

Correct answer:

s =  5.87 km

Step-by-step explanation:

16(t6010)=11t t=0.53 h s=11t s=5.87 km

16·(60t-10)=11·t·60; s = 11 t

16·(60·t-10)=11·t·60
s = 11·t

300t = 160
s-11t = 0

Pivot: Row 1 ↔ Row 2
s-11t = 0
300t = 160


t = 160/300 = 0.53333333
s = 0+11t = 0+11 · 0.53333333 = 5.86666667

s = 88/15 ≈ 5.866667
t = 8/15 ≈ 0.533333

Our linear equations calculator calculates it.



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