Calculate the length of the side GN and diagonal QN of rectangle QGNH when given: |HN| = 25 cm and angle ∠ QGH = 28 degrees.

Correct result:

|GN| =  13.29 cm
|QN| =  28.31 cm


α=28 a=HN=25 cm tanα=ba  b=GN=atanα=13.29 cm\alpha = 28 ^\circ \ \\ a = |HN| = 25 \ cm \ \\ \tan \alpha = \dfrac{ b }{ a } \ \\ \ \\ b = |GN| = a \tan \alpha = 13.29 \ \text{cm}
cosα=au u=QN=acosα=28.31 cm\cos \alpha = \dfrac{ a }{ u } \ \\ u= |QN| = \dfrac{ a }{ \cos \alpha } = 28.31 \ \text{cm}

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