Variations 4/2

Determine the number of items when the count of variations of the fourth class without repeating is 600 times larger than the count of variations of the second class without repetition.

Correct answer:

n =  27

Step-by-step explanation:

V4(n)=600V2(n) n(n1)(n2)(n3)=600n(n1) (n2)(n3)=600 n25n+6600=0 n1,2=2ab±D=25±2401 n1,2=25±49 n1,2=2.5±24.5 n1=27 n2=22 n>0 n=27 



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