Sumo competition

In the competition for the heaviest man was 5 competitors. The first three together weighed 369 kg. What is the minimal weight of the winner if a contestant weighed with an accuracy of one kilogram?

Correct answer:

m1 =  122 kg

Step-by-step explanation:

m1=33693=122=122 kg   Verifying Solution:  m2=m1+1=122+1=123 kg m3=m2+1=123+1=124 kg s=m1+m2+m3=122+123+124=369 kg



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