Combinations

How many different combinations of two-digit number divisible by four arises from the digits 3, 5, and 7?

Correct answer:

n =  6

Step-by-step explanation:

n1=32 n2=36 n3=52 n4=56 n5=72 n6=76  n=6



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Showing 1 comment:
Math student
The answer includes the digits 2, 3, 5, 6, and 7 but the problem statement only includes 3, 5, 7.





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