Freight and passenger car

The truck starts at 8 pm at 30 km/h. The passenger car starts at 8 pm at 40 km/h. Passenger arrives in the destination city 1 hour and 45 min earlier. What is the distance between the city of departure and the destination city?

Correct answer:

s =  210 km

Step-by-step explanation:


30 t = 40 (t-1.75)
s = 30 t

30·t = 40·(t-1.75)
s = 30·t

10t = 70
s-30t = 0

Pivot: Row 1 ↔ Row 2
s-30t = 0
10t = 70


t = 70/10 = 7
s = 0+30t = 0+30 · 7 = 210

s = 210
t = 7

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