Passenger car and truck

From Kutna Hora left at 11:00 clock a truck at 60 km/h. At 12:30, behind him started the passenger car at an average speed of 80 km/h. At what time and how far from Kutna Hora overtake a passenger car truck?

Result

t = 17:00 Wrong answer
s =  360 km

Step-by-step explanation:


s = 60(t-11)
s = 80(t-(12+30/60))

s = 60·(t-11)
s = 80·(t-(12+30/60))

s-60t = -660
60s-4800t = -60000

Pivot: Row 1 ↔ Row 2
60s-4800t = -60000
s-60t = -660

Row 2 - 1/60 · Row 1 → Row 2
60s-4800t = -60000
20t = 340


t = 340/20 = 17
s = -60000+4800t/60 = -60000+4800 · 17/60 = 360

s = 360
t = 17

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