Triangle ABC

In an ABC triangle, side b measure 10 cm less than side a, and side b is half of side c. Calculate the length of the sides of the circumference of the triangle as 42 cm.

Correct answer:

a =  18
b =  8
c =  16

Step-by-step explanation:


a+b+c=42
b = a-10
b = c/2

a+b+c = 42
a-b = 10
2b-c = 0

Row 2 - Row 1 → Row 2
a+b+c = 42
-2b-c = -32
2b-c = 0

Row 3 + Row 2 → Row 3
a+b+c = 42
-2b-c = -32
-2c = -32


c = -32/-2 = 16
b = -32+c/-2 = -32+16/-2 = 8
a = 42-b-c = 42-8-16 = 18

a = 18
b = 8
c = 16

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