Six-sided polygon

In a six-sided polygon. The first two angles are equal, the third angle is twice (the equal angles), two other angles are trice the equal angle, while the last angle is a right angle. Find the value of each angle.

Result

A =  63
B =  63
C =  126
D =  189
E =  189
F =  90

Solution:


A=B
C = 2B
D = E
D = 3A
F = 90
A+B+C+D+E+F = (6-2) * 180

A-B = 0
2B-C = 0
D-E = 0
3A-D = 0
F = 90
A+B+C+D+E+F = 720

A = 63
B = 63
C = 126
D = 189
E = 189
F = 90

Calculated by our linear equations calculator.







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To solve this verbal math problem are needed these knowledge from mathematics:

Do you have a system of equations and looking for calculator system of linear equations? See also our trigonometric triangle calculator.

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