Determine the discriminant of the equation:
Leave us a comment of example and its solution (i.e. if it is still somewhat unclear...):
Showing 0 comments:
Be the first to comment!
To solve this verbal math problem are needed these knowledge from mathematics:
Next similar examples:
- Variations 4/2
Determine the number of items when the count of variations of fourth class without repeating is 600 times larger than the count of variations of second class without repetition.
Determine the quadratic equation absolute coefficient q, that the equation has a real double root and the root x calculate: ?
Equation ? has one root x1 = 8. Determine the coefficient b and the second root x2.
- Quadratic equation
Find the roots of the quadratic equation: 3x2-4x + (-4) = 0.
- Quadratic function 2
Which of the points belong function f:y= 2x2- 3x + 1 : A(-2, 15) B (3,10) C (1,4)
How many elements can form six times more combinations fourth class than combination of the second class?
- Cylinder diameter
The surface of the cylinder is 149 cm2. The cylinder height is 6 cm. What is the diameter of this cylinder?
- 2nd class combinations
From how many elements you can create 4560 combinations of the second class?
Between numbers 1 and 53 insert n members of the arithmetic sequence that its sum is 702.
- Six terms
Find the first six terms of the sequence a1 = -3, an = 2 * an-1
- Solve 3
Solve quadratic equation: (6n+1) (4n-1) = 3n2
From how many elements we can create 990 combinations 2nd class without repeating?
- Reciprocal equation 2
Solve this equation: x + 5/x - 6 = 4/11
- Quadratic equation
Quadratic equation ? has roots x1 = 80 and x2 = 78. Calculate the coefficients b and c.
How much is sum of square root of six and the square root of 225?
- Median and modus
Radka made 50 throws with a dice. The table saw fit individual dice's wall frequency: Wall Number: 1 2 3 4 5 6 frequency: 8 7 5 11 6 13 Calculate the modus and median of the wall numbers that Radka fell.
- Theorem prove
We want to prove the sentense: If the natural number n is divisible by six, then n is divisible by three. From what assumption we started?