# Clock

How many times a day hands on a clock overlap?

Result

n =  22

#### Solution:

6m -0 = m/2; m = 2/11*0 = 0 min ==> 0:00:00
6m -360 = m/2; m = 2/11*360 = 65.45 min ==> 1:05:27
6m -720 = m/2; m = 2/11*720 = 130.91 min ==> 2:10:54
6m -1080 = m/2; m = 2/11*1080 = 196.36 min ==> 3:16:21
6m -1440 = m/2; m = 2/11*1440 = 261.82 min ==> 4:21:49
6m -1800 = m/2; m = 2/11*1800 = 327.27 min ==> 5:27:16
6m -2160 = m/2; m = 2/11*2160 = 392.73 min ==> 6:32:43
6m -2520 = m/2; m = 2/11*2520 = 458.18 min ==> 7:38:10
6m -2880 = m/2; m = 2/11*2880 = 523.64 min ==> 8:43:38
6m -3240 = m/2; m = 2/11*3240 = 589.09 min ==> 9:49:05
6m -3600 = m/2; m = 2/11*3600 = 654.55 min ==> 10:54:32
6m -3960 = m/2; m = 2/11*3960 = 720 min ==> 12:00:00
6m -4320 = m/2; m = 2/11*4320 = 785.45 min ==> 13:05:27
6m -4680 = m/2; m = 2/11*4680 = 850.91 min ==> 14:10:54
6m -5040 = m/2; m = 2/11*5040 = 916.36 min ==> 15:16:21
6m -5400 = m/2; m = 2/11*5400 = 981.82 min ==> 16:21:49
6m -5760 = m/2; m = 2/11*5760 = 1047.27 min ==> 17:27:16
6m -6120 = m/2; m = 2/11*6120 = 1112.73 min ==> 18:32:43
6m -6480 = m/2; m = 2/11*6480 = 1178.18 min ==> 19:38:10
6m -6840 = m/2; m = 2/11*6840 = 1243.64 min ==> 20:43:38
6m -7200 = m/2; m = 2/11*7200 = 1309.09 min ==> 21:49:05
6m -7560 = m/2; m = 2/11*7560 = 1374.55 min ==> 22:54:32
6m -7920 = m/2; m = 2/11*7920 = 1440 min ==> 24:00:00 !!! h>23

6m -8280 = m/2; m = 2/11*8280 = 1505.45 min ==> 25:05:27 !!! h>23

n=22

Leave us a comment of example and its solution (i.e. if it is still somewhat unclear...):

Showing 1 comment:
Bo Shag
I dislike these questions, but they are very good for the brain.

#### To solve this verbal math problem are needed these knowledge from mathematics:

Do you solve Diofant problems and looking for a calculator of Diofant integer equations? Do you have a linear equation or system of equations and looking for its solution? Or do you have quadratic equation? Do you want to convert length units? Try conversion angle units angle degrees, minutes, seconds, radians, grads.

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