#### Answer

$j(x)=-x^2-1$.

#### Work Step by Step

If the vertex of a quadratic function is at $(k,m)$. Then its equation can be $f(x)=\pm(x-k)^2+m$. $+$ if it is open up, $-$ if it is open down.
Hence here the function is $j(x)=-x^2-1$.

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Published by
Pearson

ISBN 10:
0-13417-894-7

ISBN 13:
978-0-13417-894-3

$j(x)=-x^2-1$.

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