Time + derivation - practice problems
Number of problems found: 9
- Acceleration 83304
The acceleration of a mass point during its rectilinear movement decreases uniformly from the initial value a0 = 10 m/s2 at time t0 = 0 to a zero value for a period of 20 s. What is the speed of the mass point at time t1 = 20 s, and what is the path of th - A particle 2
If the motion of a particle is described by the relation a(t) = 7t³ + 2 m/s², and the initial velocity of the motion is zero when t = 0 and the distance is 2m, t = 0.5s. Determine the velocity and displacement when t = 10s. - The MRT train
The MRT running from Taft to North Avenue has a starting velocity of 60km/hr. After a malfunction, the brakes failed, making the train run at a velocity of 80km/hr. What is the acceleration rate if the time for velocity change is 5 seconds? - Penny free fall
A man drops a penny from the top of a 500m tall building. After t seconds, the penny has fallen a distance of s meters, where s(t)=500-5t². Determine the average velocity between 1s and 5s. - Sleep vs. watch TV time
Using a data set relating to the number of episodes I watch on TV in a day (x) versus the number of hours of sleep I get that night (y), I construct the linear model y=−0.6x+11 Which of the following general observations can you make from this model? a) I - The shooter
The shooter shoots at the target, assuming that the individual shots are independent of each other and the probability of hitting them is 0.2. The shooter fires until he hits the target for the first time, then stop firing. (a) What is the most likely num - Shopping malls
The chain of department stores plans to invest up to 24,000 euros in television advertising. Ads will place all commercials on a television station where the broadcast of a 30-second spot costs EUR 1,000 and is watched by 14,000 potential customers. Durin - The position
The displacement function S=t³-2t²-4t-8 gives the position of a body at any time t. Find its acceleration at each instant time when the velocity is zero. - Fall
The body was thrown vertically upward at speed v0 = 39 m/s. Body height versus time describes equation h = v0 * t - (1)/(2) * 9.8 * t². What is the maximum height of body reach?
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