Circumference 7209

The speed of the points lying on the circumference of the rotating disk is 6 m/s. The speed of the points, which lie 20 cm closer to the axis of rotation, is 4 m/s. Find the angular velocity of the wheel.

Correct answer:

o =  10 1/s

Step-by-step explanation:

v1=6 m/s v2=4 m/s d=20 cm m=20:100  m=0.2 m;  v = ω   r  v1 = o   r v2 = o   (rd)  v2 = v1/r   (rd) v2   r = v1   (rd) v2   r = v1   r  v1 d  r=v1v2v1 d=646 51=53=0.6 m  o=v1/r=6/53=6:53=6 35=36 5=330=10 1/s



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