Hard equations

If a<b and c<d and a+b all/2 = c and c+d all/2 = b, and if d-a = 60, what is b-c?

Correct answer:

s =  20

Step-by-step explanation:

(a+b)/2 = c (c+d)/2 = b d−a=60  a+b=2c c+d = 2b d−a=60  d =a+60 b=a+40 c=a+20  s = b−c s = a+40 − (a+20) = a+40−a−20  s=40−20=20

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