AMJ

There are three siblings: Anne, Maya, and Jane. Anne gave Maya and Jane as much money as each had. Then Maya gave Anne and Jane as much money as each had. Then Jane gave Anne and Maya as much money as each had. Then, each of the three siblings had 128 pesos. How much money did each have originally?

Final Answer:

A =  208
M =  112
J =  64

Step-by-step explanation:

A1​=128 M1​=128 J1​=128  A2​=A1​−A1​/2=128−128/2=64 M2​=A1​−M1​/2=128−128/2=64 J2​=J1​+A1​/2+M1​/2=128+128/2+128/2=256  A3​=A2​−A2​/2=64−64/2=32 J3​=J2​−J2​/2=256−256/2=128 M3​=M2​+A2​/2+J2​/2=64+64/2+256/2=224  M=M3​−M3​/2=224−224/2=112 J=J3​−J3​/2=128−128/2=64 A=A3​+M3​/2+J3​/2=32+224/2+128/2=208

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