The temperature 36

The temperature over the course of a day was being monitored. In the morning, the temperature was −3°F. In the middle of the day, the temperature rose to 12°F. After dark, the temperature dropped again to −6°F.

What was the average temperature for the day?

Final Answer:

m =  3.75 °F

Step-by-step explanation:

$$\begin{gathered} t_1=-3\text{°F} \\ {t}_2=12\text{°F} \\ {t}_3=-6\text{°F} \\ {m}_1=\frac{t_1+t_2}{2}=\frac{(-3)+12}{2}=\frac{9}{2}=4.5\text{°F} \\ {m}_2=\frac{t_2+t_3}{2}=\frac{12+(-6)}{2}=3\text{°F} \\ m=\frac{m_1+m_2}{2}=\frac{4.5+3}{2}=3.75\text{°F} \end{gathered}$$

Try another example