Remainder one

Find the least number, when divided by 2,3,4,5,6 and 7 leaves remainder 1 in each case.

Correct answer:

n =  421

Step-by-step explanation:

2 ...  prime number 3 ...  prime number 4=22 5 ...  prime number 6=23 7 ...  prime number LCM(2,3,4,5,6,7)=22357=420  x=LCM(2,3,4,5,6,7)=420  n=x+1=420+1=421



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