Perimeter of Rhombus Problems - last page
Number of problems found: 54
- Diamond and diagonals
A diamond has diagonals f = 8 cm and g = 6 cm long. How long is this diamond perimeter? (Calculate it!) - The rope
A 68-centimeter-long rope is used to make a rhombus on the ground. The distance between a pair of opposite side corners is 16 centimeters. What is the distance between the other two corners? - Diagonals of rhombus
Find the length of the diagonal AC of the rhombus ABCD if its perimeter P = 112 dm and the second diagonal BD has a length of 36 dm. - Circumference 8771
Calculate a diamond's area with a circumference of 51.2 cm and a height of 9.6 cm. - Perimeter 7882
The diagonals of the diamond are 2.4 dm and 1.8 dm long. What is the perimeter of this diamond? - Circumference 4956
Calculate the circumference of a diamond whose area is 288cm square and one diagonal is 12.4cm. - Rhombus ABCD
Rhombus ABCD, |AC| = 63 cm, |BD| = 50 cm. Calculate the perimeter of the rhombus ABCD. - The diagonals
The diagonals of the KOSA diamond are 20 cm and 48 cm long. Calculate the circumference of the diamond in centimeters rounded to one unit. - Rhombus 48
A rhombus consists of four identical rhombuses with an area of 42 m². The angle alpha of each rhombus is 60°. What is its perimeter? - Diagonals 82850
How do I find the diagonals of a rhombus if its perimeter is 80dm and one diagonal is 2x larger than the other? - Diamond ABCD
In the diamond ABCD, the diagonal e = 24 cm, and the size of angle SAB is 28 degrees, where S is the intersection of the diagonals. Calculate the circumference of the diamond. - Bed 10
A bed shaped like two equilateral triangles with a common side, with a side length of 2.5 m, is to be planted with seedlings of an ornamental shrub. The gardener recommended leaving 40 cm between the individual seedlings and 10 cm of the perimeter for the - Two patches
Peter taped the wound with two rectangular patches (one over the other to form the letter X). The area sealed with both patches simultaneously had an area of 40cm² and a circumference of 30cm. One of the patches was 8cm wide. What was the width of the sec - Quadrilateral prism Calculate the surface of a quadrilateral prism according to the input: Area of the diamond base S1 = 2.8 m2, length of the base edge a = 14 dm, the prism height 1,500 mm.
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