Diamond ABCD

In the diamond ABCD is the diagonal e = 24 cm and size of angle SAB is 28 degrees, where S is the intersection of the diagonals. Calculate the circumference of the diamond.

Correct result:

x =  54.36 cm

Solution:

$x=4\cdot (24\mathrm{/}2)\mathrm{/}\cos 28^{\circ }=\cos 7\pi \mathrm{/}45=0=54.36\text{ cm}$

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