Diamond ABCD

In the diamond ABCD, the diagonal e = 24 cm, and the size of angle SAB is 28 degrees, where S is the intersection of the diagonals. Calculate the circumference of the diamond.

Correct answer:

x =  54.36 cm

Step-by-step explanation:

e=24 cm φ=28   w=e/2=24/2=12 cm  cos φ = w: a  a=w/cosφ=w/cos28° =12/cos28° =12/0.882948=13.59084 cm  x=4 a=4 13.5908=54.36 cm

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