Diamond ABCD

In the diamond ABCD is the diagonal e = 24 cm and size of angle SAB is 28 degrees, where S is the intersection of the diagonals. Calculate the circumference of the diamond.

Result

x =  54.36 cm

Solution:

x=4⋅ (24/2)/cos⁡(28∘→ rad)=4⋅ (24/2)/cos⁡(28∘⋅ π180 )=4⋅ (24/2)/cos⁡(28∘⋅ 3.1415926180 )=0=54.36 cmx=4 \cdot \ (24/2)/\cos( 28 ^\circ \rightarrow\ \text{rad})=4 \cdot \ (24/2)/\cos( 28 ^\circ \cdot \ \dfrac{ \pi }{ 180 } \ )=4 \cdot \ (24/2)/\cos( 28 ^\circ \cdot \ \dfrac{ 3.1415926 }{ 180 } \ )=0=54.36 \ \text{cm}

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