Trapezium diagonals

It is given trapezium ABCD with bases | AB | = 12 cm, |CD| = 8 cm. Point S is the intersection of the diagonals for which |AS| is 6 cm long. Calculate the length of the full diagonal AC.

Correct result:

x =  10 cm

Solution:

a=12 cm c=8 cm f1=6 cm  f1:a=f2:c  f2=f1 ca=6 812=4 cm  x=f1+f2=6+4=10 cm



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