​​trapezium 3428

Given is a trapezoid ABCD with bases AB, CD. Let K be side AB's midpoint, and point L be side CD's midpoint. The area of ​​triangle ALB is 15 cm2, and the area of ​​triangle DKC is 10 cm2. Calculate the area of ​​trapezium ABCD.

Correct answer:

S =  25 cm2

Step-by-step explanation:

S1=15 cm2 S2=10 cm2  S1 = a v / 2  S2 = c v / 2 k=S1/S2=15/10=23=1.5  S = (a+c)v/2 = av/2 +cv/2 = S1+S2 S=S1+S2=15+10=25 cm2

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