Diagonal intersect

Isosceles trapezoid ABCD with length bases | AB | = 6 cm, CD | = 4 cm is divided into four triangles by the diagonals intersecting at point S. How much of the area of the trapezoid are ABS and CDS triangles?

Correct answer:

r1 =  0.36
r2 =  0.16

Step-by-step explanation:

a=6 cm c=4 cm  h = h1+h2 h1:h2 = a:c  h1 = h  a+ca  S = 2a+c   h  S1= 2a h1 S2= 2c h2  r1 = S1/S = 2a h1 / 2(a+c) h r1 = (a+c) ha h1  r1 = (a+c) ha h  a+ca r1 = (a+c)a  a+ca  r1=(a+c)2a2=(6+4)262=259=0.36
r2 = S2/S = 2c h2 / 2(a+c) h r2 = (a+c) hc h2  r2 = (a+c) hc h  a+cc r2 = (a+c)c  a+cc  r2=(a+c)2c2=(6+4)242=254=0.16

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Check out our ratio calculator.
Calculation of an isosceles triangle.
See also our trigonometric triangle calculator.

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