Diagonal intersect

Isosceles trapezoid ABCD with length bases | AB | = 6 cm, CD | = 4 cm is divided into four triangles by the diagonals intersecting at point S. How much of the area of the trapezoid are ABS and CDS triangles?

Correct answer:

r1 =  0.36
r2 =  0.16

Step-by-step explanation:

a=6 cm c=4 cm  h=h1+h2 h1:h2=a:c  h1=h a+ca  S=2a+c h  S1=2a h1 S2=2c h2  r1=S1/S=2a h1/2(a+c) h r1=(a+c) ha h1  r1=(a+c) ha h a+ca r1=(a+c)a a+ca  r1=(a+c)2a2=(6+4)262=259=0.36
r2=S2/S=2c h2/2(a+c) h r2=(a+c) hc h2  r2=(a+c) hc h a+cc r2=(a+c)c a+cc  r2=(a+c)2c2=(6+4)242=254=0.16



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