Trapezoidal prism

Calculate the surface of the quadrilateral prism ABCDA'B'C'D 'with the trapezoidal base ABCD. The height of the prism is 12 cm; ABCD trapezoidal data: AB base length is 8 cm, CD base length is 3 cm, BC arm length is 4 cm, and AC diagonal length is 7 cm.
Little help: Draw the trapezoid ABCD and measure its height and the arm AD.

Correct result:

S =  274.301 cm2

Solution:

h=12 cm a=8 cm c=3 cm b=4 cm u=7 cm h1=3.499 cm S1=(a+c) h1/2=(8+3) 3.499/2=19.2445 cm2 d=4.651 cm o=a+b+c+d=8+4+3+4.651=19.651 cm S=o h+2 S1=19.651 12+2 19.2445=274.301 cm2h=12 \ \text{cm} \ \\ a=8 \ \text{cm} \ \\ c=3 \ \text{cm} \ \\ b=4 \ \text{cm} \ \\ u=7 \ \text{cm} \ \\ h_{1}=3.499 \ \text{cm} \ \\ S_{1}=(a+c) \cdot \ h_{1} /2=(8+3) \cdot \ 3.499 /2=19.2445 \ \text{cm}^2 \ \\ d=4.651 \ \text{cm} \ \\ o=a+b+c+d=8+4+3+4.651=19.651 \ \text{cm} \ \\ S=o \cdot \ h + 2 \cdot \ S_{1}=19.651 \cdot \ 12 + 2 \cdot \ 19.2445=274.301 \ \text{cm}^2

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