Rhombus diagonals

In the rhombus ABCD are given the sizes of diagonals e = 24 cm; f = 10 cm. Calculate the side length of the diamond and the size of the angles, calculate the content of the diamond

Correct result:

a =  13 cm
A =  45.2397 °
B =  134.7603 °
S =  120 cm2


e=24 cm f=10 cm  a=(e/2)2+(f/2)2=(24/2)2+(10/2)2=13 cm
 sinA/2=f/2:a  A=2 180πarcsin(f/2/a)=2 180πarcsin(10/2/13)=45.2397=451423"
 sinB/2=e/2:a  B=2 180πarcsin(e/2/a)=2 180πarcsin(24/2/13)=134.7603=1344537"
S=e f2=24 102=120 cm2

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