Intersection 81594

Given a trapezoid ABCD and the sizes of the interior angles.
Angle SDC 32°
SAD angle 33°
SDA angle 77°
Angle CBS 29°, where S is the intersection of the diagonals.
What is the size of the angle BSA?

Correct answer:

x =  110 °

Step-by-step explanation:

SDC=32  SAD=33  SDA=77  CBS=29   ASD=180SADSDA=1803377=70  CSB=ASD=70=70   x =  BSA x=180CSB=18070=110



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