In trapezoid 3

In a trapezoid ABCD, the elements are given - lengths of bases a= 20cm, c= 11 cm, angle α = 63°36’ and angle β=79°36’. Calculate the lengths of the other sides and the sizes of the angles.

Correct answer:

b =  13.4576 cm
d =  14.7776 cm
γ =  100.4 °
δ =  116.4 °

Step-by-step explanation:

$d=\sqrt{h^2+x_1^2}=\sqrt{13.2365^2+6.5706^2}=14.7776\text{cm}$

$\gamma =180-\beta =180-79.6=100.4^{\circ }=100°24^{\prime }$

$\delta =180-\alpha =180-63.6=116.4^{\circ }=116°24^{\prime }$

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