A trapezoid

A trapezoid with a base length of a = 36.6 cm, with angles α = 60°, β = 48°, and the height of the trapezoid is 20 cm. Calculate the lengths of the other sides of the trapezoid.

Final Answer:

b =  23.094 cm
d =  26.9127 cm
c =  5.1356 cm

Step-by-step explanation:

$$\begin{gathered} a=36.6\text{cm} \\ \alpha =60{}^{\circ } \\ \beta =48{}^{\circ } \\ h=20\text{cm} \\ \sin \alpha =h:b \\ b=h/\sin (\alpha )=20/\sin (60°)=23.094\text{cm} \end{gathered}$$

$$\begin{gathered} \sin \beta =h:d \\ d=h/\sin (\beta )=20/\sin (48°)=26.9127\text{cm} \end{gathered}$$

$$\begin{gathered} x_1+c+x_2=a \\ \cos \alpha =x_1:d \\ \cos \beta =x_2:d \\ c=a-d\cdot (\cos \alpha +\cos \beta )=a-d\cdot (\cos 60°+\cos 48°)=36.6-26.9127\cdot (\cos 60°+\cos 48°)=36.6-26.9127\cdot (0.5+0.669131)=5.136=5.1356\text{cm} \end{gathered}$$

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