# Angles

The triangle is one outer angle 158°54' and one internal angle 148°. Calculate the other internal angles of a triangle.

Result

A =  21.1 °
B =  10.9 °

#### Solution:

$A = 180 - 158.9 = 21.1 = \dfrac{ 211 }{ 10 } = 21.1 ^\circ = 21^\circ 6'$
$C = 148 \ ^\circ \ \\ B = 180 - (A+C) = 180 - (21.1+148) = \dfrac{ 109 }{ 10 } = 10.9 = 10.9 ^\circ = 10^\circ 54'$

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