# Angles

The triangle is one outer angle 158°54' and one internal angle 148°. Calculate the other internal angles of a triangle.

Result

A =  21.1 °
B =  10.9 °

#### Solution:

$A = 180 - 158.9 = 21.1 = \dfrac{ 211 }{ 10 } = 21.1 ^\circ = 21^\circ 6'$
$C = 148 \ ^\circ \ \\ B = 180 - (A+C) = 180 - (21.1+148) = \dfrac{ 109 }{ 10 } = 10.9 = 10.9 ^\circ = 10^\circ 54'$ Our examples were largely sent or created by pupils and students themselves. Therefore, we would be pleased if you could send us any errors you found, spelling mistakes, or rephasing the example. Thank you!

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