# Angles

The triangle is one outer angle 158°54' and one internal angle 148°. Calculate the other internal angles of a triangle.

Correct result:

A =  21.1 °
B =  10.9 °

#### Solution:

$A=180-158.9=\frac{211}{10}={\frac{211}{10}}^{\circ }=21.{1}^{\circ }=2{1}^{\circ }{6}^{\mathrm{\prime }}$

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