Angles

The triangle is one outer angle 158°54' and one internal angle 148°. Calculate the other internal angles of a triangle.

Result

A =  21.1 °
B =  10.9 °

Solution:

A=180158.9=21.1=21110=21.1=216A = 180 - 158.9 = 21.1 = \dfrac{ 211 }{ 10 } = 21.1 ^\circ = 21^\circ 6'
C=148  B=180(A+C)=180(21.1+148)=10910=10.9=10.9=1054C = 148 \ ^\circ \ \\ B = 180 - (A+C) = 180 - (21.1+148) = \dfrac{ 109 }{ 10 } = 10.9 = 10.9 ^\circ = 10^\circ 54'



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