Angles

The outer angle of the triangle ABC at the vertex A is 114°12'. The outer angle at the vertex B is 139°18'. What size is the internal angle at the vertex C?

Result

γ =  73.5 °

Solution:

 α=11412=114.2 β=13918=139.3 γ=114.2+139.3180=7330=73.5 \ \\ \alpha = 114^\circ 12' = 114.2 ^\circ \ \\ \beta = 139^\circ 18' = 139.3 ^\circ \ \\ \gamma = 114.2 ^\circ +139.3 ^\circ -180 ^\circ = 73^\circ 30' =73.5 ^\circ



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