Isosceles 83247

Calculate the lengths of the sides in an isosceles triangle, given the height (to the base) Vc= 8.8cm and the angle at the base alpha= 38°40`.

Correct answer:

a =  14.0848 cm
b =  14.0848 cm
c =  21.9946 cm

Step-by-step explanation:

v3=8.8 cm α=38°40=38°+6040°=38.6667°38.6667  sinα=v3:a=8.8:14.0848==0:0  a=v3/sinα=v3/sin38.666666666667° =8.8/sin38.666666666667° =8.8/0.624789=14.085=14.0848 cm
a=b b=a=14.0848=14.0848 cm
cos α = (c/2) : a  c/2 = a cos α c=2 a cosα=2 a cos38.666666666667° =2 14.0848 cos38.666666666667° =2 14.0848 0.780794=21.995=21.9946 cm

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