A kite

ABCD is a kite. Angle OBC = 20° and angle OCD = 35°. O is the intersection of diagonals. Find angle ABC, angle ADC and angle BAD.

Correct result:

x =  40 °
y =  110 °
z =  55 °

Solution:

OBC=20  OCD=35   OBA=OBC=20=20  ABC=OBA+OBC=20+20=40   x=ABC=40=40
OAD=OCD=35=35  ADO=90OAD=9035=55  ODC=ADO=55=55   ADC=ADO+ODC=55+55=110   y=ADC=110=110
BAD=OBA+OAD=20+35=55   z=BAD=55=55



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