A kite

ABCD is a kite. Angle OBC = 20° and angle OCD = 35°. O is the intersection of diagonals. Find angle ABC, angle ADC, and angle BAD.

Final Answer:

x =  40 °
y =  110 °
z =  55 °

Step-by-step explanation:

∠OBC=20 ∘ ∠OCD=35 ∘  ∠OBA=∠OBC=20=20 ∘ ∠ABC=∠OBA+∠OBC=20+20=40 ∘  x=∠ABC=40=40∘
∠OAD=∠OCD=35=35 ∘ ∠ADO=90−∠OAD=90−35=55 ∘ ∠ODC=∠ADO=55=55 ∘  ∠ADC=∠ADO+∠ODC=55+55=110 ∘  y=∠ADC=110=110∘
∠BAD=∠OBA+∠OAD=20+35=55 ∘  z=∠BAD=55=55∘

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algebraplanimetricsUnits of physical quantitiesGrade of the word problem

 
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