A kite

ABCD is a kite. Angle OBC = 20° and angle OCD = 35°. O is the intersection of diagonals. Find angle ABC, angle ADC and angle BAD.

Correct answer:

x =  40 °
y =  110 °
z =  55 °

Step-by-step explanation:

OBC=20 ° OCD=35 °  OBA=OBC=20 ° ABC=OBA+OBC=20+20=40 °  x=ABC=40=40°
OAD=OCD=35 ° ADO=90OAD=9035=55 ° ODC=ADO=55 °  ADC=ADO+ODC=55+55=110 °  y=ADC=110=110°
BAD=OBA+OAD=20+35=55 °  z=BAD=55=55°



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