A kite

ABCD is a kite. Angle OBC = 20° and angle OCD = 35°. O is the intersection of diagonals. Find angle ABC, angle ADC, and angle BAD.

Correct answer:

x =  40 °
y =  110 °
z =  55 °

Step-by-step explanation:

∠OBC=20 ∘ ∠OCD=35 ∘  ∠OBA=∠OBC=20=20 ∘ ∠ABC=∠OBA+∠OBC=20+20=40 ∘  x=∠ABC=40=40∘
∠OAD=∠OCD=35=35 ∘ ∠ADO=90−∠OAD=90−35=55 ∘ ∠ODC=∠ADO=55=55 ∘  ∠ADC=∠ADO+∠ODC=55+55=110 ∘  y=∠ADC=110=110∘
∠BAD=∠OBA+∠OAD=20+35=55 ∘  z=∠BAD=55=55∘

Try another example


Did you find an error or inaccuracy? Feel free to write us. Thank you!







Tips for related online calculators
See also our right triangle calculator.
See also our trigonometric triangle calculator.

You need to know the following knowledge to solve this word math problem:

algebraplanimetricsUnits of physical quantitiesGrade of the word problem

 
We encourage you to watch this tutorial video on this math problem: video1

Related math problems and questions: