The intersection of the diagonals

In the rectangular coordinate system, a rectangle ABCD is drawn. These coordinates determine the vertices of the rectangle:
A = (2.2)
B = (8.2)
C = (8.6)
D = (2.6)

Find the coordinates of the intersection of the diagonals of the ABCD rectangle.

Correct answer:

x =  5
y =  4

Step-by-step explanation:

$$\begin{gathered} u=AC \\ S=AC/2 \\ {A}_0=2;A_1=2 \\ {C}_0=8;C_1=6 \\ x=\frac{A_0+C_0}{2}=\frac{2+8}{2}=5 \end{gathered}$$

$y=\frac{A_1+C_1}{2}=\frac{2+6}{2}=4$

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