Trapezoid - interior angles

In the trapezoid ABCD (AB II CD) is α = 57°, γ = 4β. Calculate the size of all interior angles.

Final Answer:

α =  57 °
β =  36 °
γ =  144 °
δ =  123 °

Step-by-step explanation:

α=57=57
 γ = 4 β  α+δ = 180    β+γ = 180    β+4 β=180  5β=180  β=5180=36  β=36=36
γ=4 β=4 36=144
δ=180α=18057=123



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