Trapezoid: 18703

In the ABCD trapezoid: | AD | = | CD | = | BC | a | AB | = | AC |. Determine the size of the delta angle.

Correct answer:

D =  108 °

Step-by-step explanation:

 sin D/2 = y/2 : x cos A = (yx)/2 : x A+D = pi  D1=π180°3/5π=π180°3/5 3.1416=108  D2=π180°7/5π=π180°7/5 3.1416=252  D3=π180°11/5π=π180°11/5 3.1416=396  D4=π180°1/5π=π180°1/5 3.1416=36    0 < D < 180°  D=D1=108=108

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