Rhombus and diagonals

The lengths of the diamond diagonals are e = 48cm, f = 20cm. Calculate the length of its sides.

Correct answer:

a =  26 cm

Step-by-step explanation:

$$\begin{gathered} e=48\text{ cm } \\ f=20\text{ cm } \\ {a}^2=(e\mathrm{/}2{)}^2+(f\mathrm{/}2{)}^2 \\ a=\sqrt{(e\mathrm{/}2{)}^2+(f\mathrm{/}2{)}^2}=\sqrt{(48\mathrm{/}2{)}^2+(20\mathrm{/}2{)}^2}=26\text{ cm} \end{gathered}$$

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