The perimeter

The perimeter of a rhombus whose diagonal lengths are in the ratio 3:4 is 40 cm. What is its area in cm²?

Correct answer:

A =  96 cm2

Step-by-step explanation:

o=40 cm e:f=3:4  o=4a  a=o/4=40/4=10 cm  (e/2)2 +(f/2)2 = a2  (3x/2)2 +(4x/2)2 = a2 9x2/4 +16x2/4 = a2  9x2 +16x2 = 4 a2 x=9+164 a2=9+164 102=4 cm  e=3 x=3 4=12 cm f=4 x=4 4=16 cm  A=2e f=212 16=96 cm2

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