Two diagonals

The diagonals of the diamond EFGH have lengths in the ratio 1: 2. What is the circumference of a rhombus if the longer of the diagonals is 8 cm long?

Correct answer:

o =  17.8885 cm

Step-by-step explanation:

u1=8 cm u2:u1=1:2 u2=1/2 u1=1/2 8=4 cm  a2=(u1/2)2+(u2/2)2  a=(u1/2)2+(u2/2)2=(8/2)2+(4/2)2=2 5 cm4.4721 cm  o=4 a=4 4.4721=8 517.8885 cm   Verifying Solution:  t=u2/u1=4/8=12=0.5



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Tips to related online calculators
Pythagorean theorem is the base for the right triangle calculator.
See also our trigonometric triangle calculator.

 
We encourage you to watch this tutorial video on this math problem: video1   video2   video3

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