Rhombus diagonal perimeter

How do I find the diagonals of a rhombus if its perimeter is 80 dm and one diagonal is 2x larger than the other?

Final Answer:

u =  35.7771 dm
v =  17.8885 dm

Step-by-step explanation:

o=80 dm u = 2v  o = 4a  a=o/4=80/4=20 dm  (u/2)2 + (v/2)2 = a2  (u/2)2 + (u/4)2 = a2  u2/4 + u2/16 = a2  u=a/1/4+1/16​=20/1/4+1/16​=16 5​=35.7771 dm
v=u/2=35.7771/2=8 5​≐17.8885 dm   Verifying Solution:   a2​=(u/2)2+(v/2)2​=(35.7771/2)2+(17.8885/2)2​=20 dm

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algebraarithmeticplanimetryUnits of physical quantitiesGrade of the word problem

 
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