Diagonals of a rhombus

One of the diagonals of a rhombus is twice as the other. If the sum of the lengths of the diagonals is 24, find the area of the rhombus.

Correct result:

S =  64

Solution:

u1+u2=24 u1=2 u2 2u2+u2=24 u2=24/3=8 u1=2 u2=2 8=16 S=u1 u2/2=16 8/2=64



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