Line slope calculator 5x-3y=-9
Straight line given by points A[0; 3] and B[3; 8]
Calculation:
Slope: m = 1.6667Slope-intercept form of line: y = 1.6667x+3
Canonical form of the line equation: 5x-3y+9 = 0
Parametric form of the line equation:
x = 3t
y = 5t+3 ; t ∈ R
Slope angle of line: φ = 59°2'10″ = 1.0304 rad
X intercept: x0 = -1.8
Y intercept: y0 = q = 3
Distance line from the origin: d0 = 1.5435
The length of the segment AB: |AB| = 5.831
Vector: AB = (3; 5)
Normal vector: n = (5; -3)
Midpoint of the segment AB: M = [1.5; 5.5]
Perpendicular Bisector equation: 3x+5y-32 = 0
Vector OA = (0; 3) ; |OA| = 3
Vector OB = (3; 8) ; |OB| = 8.544
Scalar product OA .OB = 24
Angle ∠ AOB = 20°33'22″ = 0.3588 rad