# Combinatorial calculator

Find out how many different ways you can choose*k*items from

*n*items set. With/without repetition, with/without order.

## Calculation:

$C_{k}(n)=(kn )=k!(n−k)!n! n=10k=4C_{4}(10)=(410 )=4!(10−4)!10! =4⋅3⋅2⋅110⋅9⋅8⋅7 =210$

### Number of combinations: 210

# A bit of theory - foundation of combinatorics

## Variations

A variation of the k-th class of n elements is an ordered k-element group formed from a set of n elements. The elements are not repeated and depend on the order of the group's elements (therefore arranged).The number of variations can be easily calculated using the combinatorial rule of product. For example, if we have the set n = 5 numbers 1,2,3,4,5 and we have to make third-class variations, their V

_{3}(5) = 5 * 4 * 3 = 60. $V_{k}(n)=n(n−1)(n−2)...(n−k+1)=(n−k)!n! $ n! we call the factorial of the number n, which is the product of the first n natural numbers. The notation with the factorial is only clearer, equivalent. For calculations, it is fully sufficient to use the procedure resulting from the combinatorial rule of product.

## Permutations

The permutation is a synonymous name for a variation of the nth class of n-elements. It is thus any n-element ordered group formed of n-elements. The elements are not repeated and depend on the order of the elements in the group. $P(n)=n(n−1)(n−2)...1=n!$ A typical example is: We have 4 books, and in how many ways can we arrange them side by side on a shelf?## Variations with repetition

A variation of the k-th class of n elements is an ordered k-element group formed of a set of n elements, wherein the elements can be repeated and depends on their order. A typical example is the formation of numbers from the numbers 2,3,4,5, and finding their number. We calculate their number according to the combinatorial rule of the product: $V_{k}(n)=n⋅n⋅n⋅n...n=n_{k}$## Permutations with repeat

A repeating permutation is an arranged k-element group of n-elements, with some elements repeating in a group. Repeating some (or all in a group) reduces the number of such repeating permutations. $P_{k_{1}k_{2}k_{3}...k_{m}}(n)=k_{1}!k_{2}!k_{3}!...k_{m}!n! $ A typical example is to find out how many seven-digit numbers formed from the numbers 2,2,2, 6,6,6,6.## Combinations

A combination of a k-th class of n elements is an unordered k-element group formed from a set of n elements. The elements are not repeated, and it does not matter the order of the group's elements. In mathematics, disordered groups are called sets and subsets. Their number is a combination number and is calculated as follows: $C_{k}(n)=(kn )=k!(n−k)!n! $ A typical example of combinations is that we have 15 students and we have to choose three. How many will there be?## Combinations with repeat

Here we select k element groups from n elements, regardless of the order, and the elements can be repeated. k is logically greater than n (otherwise, we would get ordinary combinations). Their count is: $C_{k}(n)=(kn+k−1 )=k!(n−1)!(n+k−1)! $ Explanation of the formula - the number of combinations with repetition is equal to the number of locations of n − 1 separators on n-1 + k places. A typical example is: we go to the store to buy 6 chocolates. They offer only 3 species. How many options do we have? k = 6, n = 3.## Foundation of combinatorics in word problems

- Chords

How many 4-tones chords (chord = at the same time sounding different tones) is possible to play within 7 tones? - Cards

The player gets eight cards of 32. What is the probability that it gets a) all four aces b) at least one ace - Soccer teams

Have to organize soccer teams. There are 3 age groups. How many different ways can you organize teams of ten for each age group? Is this a permutation or combination? - Three digits number 2

Find the number of all three-digit positive integers that can be put together from digits 1,2,3,4 and which are subject to the same time has the following conditions: on one positions is one of the numbers 1,3,4, on the place of hundreds 4 or 2. - Cards

How many ways can you give away 32 playing cards to 7 player? - Probability 40131

There are 28 students in the IK3 class. Three pupils are to be tested. Nineteen pupils are ready for the exam. What is the probability that all three will be unprepared? - C(6,3)

C(6,3) + 3 P(6,3) - Dice

We throw 10 times a playing dice. What is the probability that the six will fall exactly 4 times? - Honored students

Of the 25 students in the class, 10 are honored. How many ways can we choose 5 students from them, if there are to be exactly two honors between them? - Divisible by five

How many different three-digit numbers divisible by five can we create from the digits 2, 4, 5? We can repeat the digits in the created number. - Chambers

The decision-making committee consists of three people. In order for the commission's decision to be valid, at least two members must vote in the same way. It is not possible not to vote in the commission, everyone only votes yes or no. We assume that the - Karolína

Karolína chose 5 bodies from the kit - white, blue and gray cubes, a blue cylinder and a white triangular prism. How many different roof towers can be built one by one if all the blue bodies (cube and cylinder) are not placed on top of each other? - Tricolors

From the colors - red, blue, green, black, and white, create all possible tricolors. - Covid-19

Data showed that 22% of people in a small town were infected with the COVID-19 virus. A random sample of six residents from this town was selected. Find the probability that exactly two of these residents were infected. - An aircraft

An aircraft manufacturing company has submitted bids on two separate airline contracts, A and B. The company feels that it has a 70% chance of winning contract A and a 25% chance of winning contract B. Furthermore, it believes that winning contract A is i - Three wagons

I have 6 different people (A, B, C, D, E, F), which I have to place into 3 wagons, if it depends on who will board. How many options are there?

more math problems »