Probability - triangles
We have five lines with lengths of 3cm, 5cm, 7cm, 9cm, and 11cm. What is the probability that we will be able to construct a triangle with randomly selected three?
Correct answer:

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Dr. Math
For clarity, we list all possible triples and check whether they satisfy the triangle inequality:
1. 3, 5, 7
- 3 + 5 > 7 → 8 > 7 (yes)
- 3 + 7 > 5 → 10 > 5 (yes)
- 5 + 7 > 3 → 12 > 3 (yes)
A triangle can be constructed.
2. 3, 5, 9
- 3 + 5 > 9 → 8 > 9 (no)
A triangle cannot be constructed.
3. 3, 5, 11
- 3 + 5 > 11 → 8 > 11 (no)
A triangle cannot be constructed.
4. 3, 7, 9
- 3 + 7 > 9 → 10 > 9 (yes)
- 3 + 9 > 7 → 12 > 7 (yes)
- 7 + 9 > 3 → 16 > 3 (yes)
A triangle can be constructed.
5. 3, 7, 11
- 3 + 7 > 11 → 10 > 11 (no)
A triangle cannot be constructed.
6. 3, 9, 11
- 3 + 9 > 11 → 12 > 11 (yes)
- 3 + 11 > 9 → 14 > 9 (yes)
- 9 + 11 > 3 → 20 > 3 (yes)
A triangle can be constructed.
7. 5, 7, 9
- 5 + 7 > 9 → 12 > 9 (yes)
- 5 + 9 > 7 → 14 > 7 (yes)
- 7 + 9 > 5 → 16 > 5 (yes)
A triangle can be constructed.
8. 5, 7, 11
- 5 + 7 > 11 → 12 > 11 (yes)
- 5 + 11 > 7 → 16 > 7 (yes)
- 7 + 11 > 5 → 18 > 5 (yes)
A triangle can be constructed.
9. 5, 9, 11
- 5 + 9 > 11 → 14 > 11 (yes)
- 5 + 11 > 9 → 16 > 9 (yes)
- 9 + 11 > 5 → 20 > 5 (yes)
A triangle can be constructed.
10. 7, 9, 11
- 7 + 9 > 11 → 16 > 11 (yes)
- 7 + 11 > 9 → 18 > 9 (yes)
- 9 + 11 > 7 → 20 > 7 (yes)
A triangle can be constructed.
Of the 10 possible triples, 7 satisfy the triangle inequality, and therefore a triangle can be constructed from them.
The probability P is therefore:
The probability that a triangle can be constructed by randomly selecting a triple of line segments is 710 or 70%.
1. 3, 5, 7
- 3 + 5 > 7 → 8 > 7 (yes)
- 3 + 7 > 5 → 10 > 5 (yes)
- 5 + 7 > 3 → 12 > 3 (yes)
A triangle can be constructed.
2. 3, 5, 9
- 3 + 5 > 9 → 8 > 9 (no)
A triangle cannot be constructed.
3. 3, 5, 11
- 3 + 5 > 11 → 8 > 11 (no)
A triangle cannot be constructed.
4. 3, 7, 9
- 3 + 7 > 9 → 10 > 9 (yes)
- 3 + 9 > 7 → 12 > 7 (yes)
- 7 + 9 > 3 → 16 > 3 (yes)
A triangle can be constructed.
5. 3, 7, 11
- 3 + 7 > 11 → 10 > 11 (no)
A triangle cannot be constructed.
6. 3, 9, 11
- 3 + 9 > 11 → 12 > 11 (yes)
- 3 + 11 > 9 → 14 > 9 (yes)
- 9 + 11 > 3 → 20 > 3 (yes)
A triangle can be constructed.
7. 5, 7, 9
- 5 + 7 > 9 → 12 > 9 (yes)
- 5 + 9 > 7 → 14 > 7 (yes)
- 7 + 9 > 5 → 16 > 5 (yes)
A triangle can be constructed.
8. 5, 7, 11
- 5 + 7 > 11 → 12 > 11 (yes)
- 5 + 11 > 7 → 16 > 7 (yes)
- 7 + 11 > 5 → 18 > 5 (yes)
A triangle can be constructed.
9. 5, 9, 11
- 5 + 9 > 11 → 14 > 11 (yes)
- 5 + 11 > 9 → 16 > 9 (yes)
- 9 + 11 > 5 → 20 > 5 (yes)
A triangle can be constructed.
10. 7, 9, 11
- 7 + 9 > 11 → 16 > 11 (yes)
- 7 + 11 > 9 → 18 > 9 (yes)
- 9 + 11 > 7 → 20 > 7 (yes)
A triangle can be constructed.
Of the 10 possible triples, 7 satisfy the triangle inequality, and therefore a triangle can be constructed from them.
The probability P is therefore:
P = Number of favorable triplesTotal number of triples = 710 = 0{.}7
The probability that a triangle can be constructed by randomly selecting a triple of line segments is 710 or 70%.
11 days ago 1 Like
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