Dice

How many times must throw the dice, the probability of throwing at least one six was greater than 90%?

Correct answer:

It should throw the dice:  13 times

Step-by-step explanation:

$n=\lceil {\displaystyle \frac{log(1-{\displaystyle \frac{90}{100}})}{log({\displaystyle \frac{5}{6}})}}\rceil =13\text{ times}$

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