Dice

How many times must throw the dice, the probability of throwing at least one six was greater than 90%?

Correct result:

It should throw the dice:  13 times

Solution:

n=log(190100)log(56)=13 timesn = \lceil \dfrac{ log(1-\dfrac{ 90}{100})}{log(\dfrac{5}{6})} \rceil = 13 \ \text{times}



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